I have to parse a string which contains a formula for my java project and I wanted to use the package exp4j (http://www.objecthunter.net/exp4j/index.html) to do so. But I always get the same error. Its probably really stupid, but sadly I'm missing it. So here is, what I tried:
I simply tried this for testing:
import de.congrace.exp4j.Calculable;
import de.congrace.exp4j.ExpressionBuilder;
public class Tester {
public static void main (String[] args){
Calculable calc = new ExpressionBuilder("3+2").build();
}
}
Now eclipse tells me Unhandled exception type UnknownFunctionExpression and Unhandled exception type UnparsableExpressionException.
After that I tried just using one of the examples on the mentioned website:
import de.congrace.exp4j.Calculable;
import de.congrace.exp4j.ExpressionBuilder;
public class Tester {
public static void main (String[] args){
double varX = 2;
double varY = 3;
Calculable calc = new ExpressionBuilder("3 * sin(y) - 2 / (x - 2)")
.withVariable("x", varX)
.withVariable("y", varY)
.build();
double result1=calc.calculate();
}
}
resulting in the same exceptions as above.
Sorry for any bad english, I'm german and thanks for any help :)
The error tells you that a checked exception might occur, so you have to handle it yourself.
you could either use try/catch to handle it or just declare the exception using throws clause
public static void main (String[] args) throws UnparsableExpressionException{
Calculable calc = new ExpressionBuilder("3+2").build();
}
or you can wrap the code in a try/catch to handle the exception.
try {
Calculable calc = new ExpressionBuilder("3+2").build();
}
catch(UnparsableExpressionException ex){
ex.printstacktrace();
}
follow the same for UnknownFunctionExpression as well.
and read about Exceptional Handling in java here
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