I'm trying to use queue.PriorityQueue
in Python 3(.6).
I would like to store objects with a given priority. But if two objects have the same priority, I don't mind PriorityQueue.get
to return either. In other words, my objects can't be compared at integers, it won't make sense to allow them to be, I just care about the priority.
In Python 3.7's documentation, there's a solution involving dataclasses
. And I quote:
If the data elements are not comparable, the data can be wrapped in a class that ignores the data item and only compares the priority number:
from dataclasses import dataclass, field
from typing import Any
@dataclass(order=True)
class PrioritizedItem:
priority: int
item: Any=field(compare=False)
Alas, I'm using Python 3.6. In the documentation of this version of Python, there's no comment on using PriorityQueue
for the priorities, not bothering about the "object value" which wouldn't be logical in my case.
Is there a better way than to define __le__
and other comparison methods on my custom class? I find this solution particularly ugly and counter-intuitive, but that might be me.
dataclasses
is just a convenience method to avoid having to create a lot of boilerplate code.
You don't actually have to create a class. A tuple with a unique counter value too:
from itertools import count
unique = count()
q.put((priority, next(unique), item))
so that ties between equal priority are broken by the integer that follows; because it is always unique the item
value is never consulted.
You can also create a class using straight-up rich comparison methods, made simpler with @functools.total_ordering
:
from functools import total_ordering
@total_ordering
class PrioritizedItem:
def __init__(self, priority, item):
self.priority = priority
self.item = item
def __eq__(self, other):
if not isinstance(other, __class__):
return NotImplemented
return self.priority == other.priority
def __lt__(self, other):
if not isinstance(other, __class__):
return NotImplemented
return self.priority < other.priority
See priority queue implementation notes - just before the section you quoted (regarding using dataclasses
) it tells you how to do it whitout them:
... is to store entries as 3-element list including the priority, an entry count, and the task. The entry count serves as a tie-breaker so that two tasks with the same priority are returned in the order they were added. And since no two entry counts are the same, the tuple comparison will never attempt to directly compare two tasks.
So simply add your items as 3rd element in a tuple (Prio, Count, YourElem)
when adding to your queue.
Contreived example:
from queue import PriorityQueue
class CompareError(ValueError): pass
class O:
def __init__(self,n):
self.n = n
def __lq__(self):
raise CompareError
def __repr__(self): return str(self)
def __str__(self): return self.n
def add(prioqueue,prio,item):
"""Adds the 'item' with 'prio' to the 'priorqueue' adding a unique value that
is stored as member of this method 'add.n' which is incremented on each usage."""
prioqueue.put( (prio, add.n, item))
add.n += 1
# no len() on PrioQueue - we ensure our unique integer via method-param
# if you forget to declare this, you get an AttributeError
add.n = 0
h = PriorityQueue()
add(h, 7, O('release product'))
add(h, 1, O('write spec 3'))
add(h, 1, O('write spec 2'))
add(h, 1, O('write spec 1'))
add(h, 3, O('create tests'))
for _ in range(4):
item = h.get()
print(item)
Using h.put( (1, O('write spec 1')) )
leads to
TypeError: '<' not supported between instances of 'O' and 'int'`
Using def add(prioqueue,prio,item):
pushes triplets as items wich have guaranteed distinct 2nd values so our O()
-instances are never used as tie-breaker.
Output:
(1, 2, write spec 3)
(1, 3, write spec 2)
(1, 4, write spec 1)
(3, 5, create tests)
see MartijnPieters answer @here for a nicer unique 2nd element.
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