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Unicode Encode Error: 'ascii' codec can't encode character u'\u2019'

Tags:

python

unicode

I'm trying to read html file but when sourcing out for the titles and urls to compare with my keyword 'alist' I get this error Unicode Encode Error: 'ascii' codec can't encode character u'\u2019'. Error in link(http://tinypic.com/r/307w8bl/8)

Code

for q in soup.find_all('a'):
    title = (q.get('title'))
    url = ((q.get('href')))
    length = len(alist)
    i = 0
    while length > 0:
        if alist[i] in str(title): #checks for keywords from html form from the titles and urls
            r.write(title)
            r.write("\n")
            r.write(url)
            r.write("\n")
        i = i + 1
        length = length -1
doc.close()
r.close()

A little background. alist contains a list of keywords which I would use to compare it with title so as to get what I want. The strange thing is if alist contains 2 or more words, it would run perfectly but if there was only one word, the error as seen above would appear. Thanks in advance.

like image 695
Jmo Avatar asked Dec 09 '25 07:12

Jmo


1 Answers

If your list MUST BE a string list, try to encode title var

>>> alist=['á'] #asci string
>>> title = u'á' #unicode string
>>> alist[0] in title
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 0: ordinal not in range(128)
>>> title and alist[0] in title.encode('utf-8')
True
>>> 
like image 76
xecgr Avatar answered Dec 10 '25 19:12

xecgr



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