TypeScript: Getting a class/constructor of the object at runtime

Question

For debugging purposes, I want a toString() method of an abstract class to print of which subclass the instance actually is.

abstract FrameModel {
    ...
    public toString() {
        var classOfThis = ?????;
        return `FrameModel<${classOfThis}>#${this.vertexId}`;
    }
}

Also it would be great if I could use that class in TypeScript to access the static members; in other words, if I got the JavaScript constructor function to which TypeScript puts the static fields.

I've tried

var classOfThis = Object.getPrototypeOf(this).constructor;

But that's not it :)

Answer 1

Using Object.getPrototypeOf(this).constructor does indeed work:

type AConstructor = {
    new(): A;
    name: string;
}

abstract class A {
    toString(): string {
        return `class: ${ (Object.getPrototypeOf(this).constructor as AConstructor).name }`;
    }
}

class B extends A {}

class C extends A {}

let b = new B();
console.log(b.toString()); // class: B

let c = new C();
console.log(c.toString()); // class: C

(code in playground)

I'm not sure why it doesn't for you, I'll need to see more of your code.
In any case, you can also use: this.constructor:

toString(): string {
    return `class: ${ (this.constructor as AConstructor).name }`;
}