In the following exercise i want to manipulate a random string input by using functions.
Step 1: I want to remove all characters which are not digits, letters or spaces
Step 2: I want to replace all spaces with '_'
Step 3: I want to convert all numbers to spaces
Step 4: I want to replace all 'a' with 'z' and all 'A' with 'Z'
For lists i already used the filter function and i am wondering if this function can also be used for string inputs. I am not quite sure how to approach this exercise.
Update: I found an approach to solve step 1 and step 3 but i am not quite sure how to put the different functions together in a function which includes every step. Is it possible to call the different functions one after another in the right order in some kind of main function?
import Data.Char
toUpperStr xs = map toUpper xs -- function to convert lower to upper
dropInvalids xs = (filter (\x -> isUpper x || isSpace x || isDigit x)) $
toUpperStr xs
replaceBlank [] = [] -- function to replace " " with "_"
replaceBlank (x:xs) =
if x == ' '
then '_' : replaceBlank xs
else x : replaceBlank xs
Yes, absolutely! That's one of the beautiful things about Haskell.
You can treat String
s as [Char]
. In fact, that's what they are!
In GHCi, type :i String
- you get type String = [Char]
.
You can easily compose functions. There's an operator for that, (.)
.
So (f . g) x
is f (g x)
.
I would improve the code in a few key ways.
Firstly, make the replaceBlank
function more general, so it takes a condition and a replacement function.
Secondly, compose all the functions in a "main" function, as you call it.
But do not name the main function main
! That name is reserved for the IO action of a program.
It's also important not to think of the final function as "calling" the other functions.
That is imperative terminology, here, we are applying the function(s).
Also, why does your dropInvalids
contain a toUpperStr
? You never specified the string to be all uppercase in the end.
Also also, be sure to declare the type of your functions.
In this case, the following would be the correct code:
import Data.Char
dropInvalids :: [Char] -> [Char]
dropInvalids = filter (\x -> isLetter x || isSpace x || isDigit x)
-- isLetter exists
replace' :: (a -> Bool) -> (a -> a) -> [a] -> [a]
replace' _ _ [] = []
replace' f g (x:xs) =
if f x
then g x : replace' f g xs
else x : replace' f g xs
-- To replace one value with another, use replace (== a) (const b).
replaceWith :: (a -> Bool) -> a -> [a] -> [a]
replaceWith f b = replace' f (const b)
replace :: Eq a => a -> a -> [a] -> [a]
replace a b = replace' (== a) (const b)
-- The Eq makes sure you can check for equality.
manipulateString :: [Char] -> [Char]
manipulateString = replace 'A' 'Z' . replace 'a' 'z' . replaceWith isDigit ' ' . replace ' ' '_' . dropInvalids
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