I'm trying to run some tasks in Gulp, sequentially. One of those tasks is a shell script that performs a simple $ node app.js. How can I fire the callback so I can tell Gulp that the server has started?
tl;dr
So here's the bigger picture of what I'm trying to accomplish:
I'm using gulp run-sequence to fire up a number of tasks sequentially, which specifies a couple ways you should be writing your tasks in order for them to be run in sequence.
Each gulp.task() must either:
return the stream
orgulp.task("clean", ..); // returns the stream, all OKgulp.task("compile", ..); // returns the stream, all OKgulp.task("spin-server", ..); // calls the callback with a hackgulp.task("init-browser-sync", ..); // last taskHere's my spin-server task:
gulp.task("spin-server", function(cb) {
exec("sh shell-utilities/spin-server");
// @HACK allow time for the server to start before `runSequence`
// runs the next task.
setTimeout(function() {
cb();
}, 2500);
});
And here's the spin-server.sh shell script:
## Start Node server ##
node server/app.js
#######
# EOF #
#######
Right now I'm using a setTimeout hack to make sure my Node/Express server has fired up before proceeding to run the init-browser-sync task.
How can I eliminate that setTimeout hack and call cb() when my Express server actually fires up?
Use spawn instead of exec (require('child_process').spawn) like this :
var spawn = require('child_process').spawn;
gulp.task("spin-server", function(cb) {
var srv = spawn("sh shell-utilities/spin-server");
srv.stdout.on('data', data => {
if(data.includes('server listening')) { // Or whatever your server outputs when it's done initializing
console.log('Server initialization completed');
return cb();
}
});
});
When the string server listening is found in the output of the spawned process, the cb() is called and the server is guaranteed to be initialized at that point.
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