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split a String with a separator in trailing position in Scala

Tags:

scala

The method split do NOT deal with the separator in trailing position.

@ "a-b-".split("-")
res9: Array[String] = Array("a", "b")

However, I would expect Array("a", "b", "")

Any way to fix that ?

like image 237
Yann Moisan Avatar asked Oct 26 '25 15:10

Yann Moisan


1 Answers

You may pass additional parameter limit to the function (which is zero by default):

scala> "a-b-".split("-", -1)
res3: Array[String] = Array(a, b, "")

scala> "-----".split("-", -1)
res4: Array[String] = Array("", "", "", "", "", "")

Documentation:

The limit parameter controls the number of times the pattern is applied and therefore affects the length of the resulting array. If the limit n is greater than zero then the pattern will be applied at most n - 1 times, the array's length will be no greater than n, and the array's last entry will contain all input beyond the last matched delimiter. If n is non-positive then the pattern will be applied as many times as possible and the array can have any length. If n is zero then the pattern will be applied as many times as possible, the array can have any length, and trailing empty strings will be discarded.

like image 178
awesoon Avatar answered Oct 29 '25 10:10

awesoon



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