I have a spark dataframe for which I need to filter nulls and spaces for a particular column.
Lets say dataframe has two columns. col2 has both nulls and also blanks.
col1 col2
1 abc
2 null
3 null
4
5 def
I want to apply a filter out the records which have col2 as nulls or blanks. Can any one please help on this.
Version: Spark1.6.2 Scala 2.10
The standard logical operators are defined on Spark Columns:
scala> val myDF = Seq((1, "abc"),(2,null),(3,null),(4, ""),(5,"def")).toDF("col1", "col2")
myDF: org.apache.spark.sql.DataFrame = [col1: int, col2: string]
scala> myDF.show
+----+----+
|col1|col2|
+----+----+
| 1| abc|
| 2|null|
| 3|null|
| 4| |
| 5| def|
+----+----+
scala> myDF.filter(($"col2" =!= "") && ($"col2".isNotNull)).show
+----+----+
|col1|col2|
+----+----+
| 1| abc|
| 5| def|
+----+----+
Note: depending on your Spark version you will need !== or =!= (the latter is the more current option).
If you had n conditions to be met I would probably use a list to reduce the boolean columns together:
val conds = List(myDF("a").contains("x"), myDF("b") =!= "y", myDF("c") > 2)
val filtered = myDF.filter(conds.reduce(_&&_))
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