Sort list by Alphanumeric with decimal

Question

I have a List<string> that I need to sort by alphanumeric but it also has a decimal. The sample looks like this:

E11.9
E13.9
E10.9
E11.65
E10.65
E11.69
E13.10
E10.10

The output I need should look like this:
E10.10
E10.65
E10.9
E11.69
E11.9
etc..

I've tried this code:

result.Sort((s1, s2) =>
{
    string pattern = "([A-Za-z])([0-9]+)";
    string h1 = Regex.Match(s1, pattern).Groups[1].Value;
    string h2 = Regex.Match(s2, pattern).Groups[1].Value;
    if (h1 != h2)
        return h1.CompareTo(h2);
    string t1 = Regex.Match(s1, pattern).Groups[2].Value;
    string t2 = Regex.Match(s2, pattern).Groups[2].Value;
    return int.Parse(t1).CompareTo(int.Parse(t2));
});

But it only seems to sort by the Letter first, then by the digits prior to the decimal place. So this is what I get:
E10.9
E10.65
E10.10
E11.9
E11.69
etc..

Am I missing something in the regex? Or is there a better way to accomplish this?

Answer 1

Can you just do this?:

Test data:

var ls=new List<string>
    {
    "E11.9",
    "E13.9",
    "E10.9",
    "E11.65",
    "E10.65",
    "E11.69",
    "E13.10",
    "E10.10",
    };

Linq:

var result= ls
             .OrderBy (l =>l.Substring(0,1))
             .ThenBy(l =>double.Parse(l.Substring(1), CultureInfo.InvariantCulture))
             .ToList();

Answer 2

Building on Arion's answer:

var result = list.OrderBy(l => l[0]).ThenBy(l => double.Parse(l.Substring(1));

So first you'd sort by the letter and after that by the number after the letter. In case you need to handle different culture settings in double.Parse, you'd have to supply that there. See MSDN on Double.Parse.