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Simple operation on Structure in CUDA : Segmentation fault [duplicate]

Tags:

cuda

This is the first time I am implementing structures in CUDA. In the following program I am copying a structure to the GPU and performing a basic operation on the data, and copying back the result to the Host.

#include<stdio.h>

inline cudaError_t checkCuda(cudaError_t result)
{
    #if defined(DEBUG) || defined(_DEBUG)
        if (result != cudaSuccess) {
            fprintf(stderr, "CUDA Runtime Error: %sn", cudaGetErrorString(result));
        assert(result == cudaSuccess);
        }
    #endif
    return result;
}

typedef struct myStruct {
    int* a;
    int b;
}MyStruct;

__global__ void structOperation(MyStruct *d_data){
    int idx = threadIdx.x;

    d_data->a[idx] += 10;
}

int main(){
    MyStruct *h_data, *d_data, *out_data;

    size_t structSize = sizeof(MyStruct);
    size_t intSize = sizeof(int);


    h_data = (MyStruct *) malloc(structSize * 1);
    h_data->b = 32;
    h_data->a = (int *)malloc(intSize * h_data->b);

    out_data = (MyStruct *) malloc(structSize * 1);
    out_data->b = 32;
    out_data->a = (int *)malloc(intSize * out_data->b);

    for(int i = 0; i<32; i++){
        h_data->a[i] = i;   
    }

    //Memory allocation for the Struct
    checkCuda(cudaMalloc(&d_data, sizeof(MyStruct) * 1));
    checkCuda(cudaMalloc(&(d_data->a), sizeof(int) * 32));


    checkCuda(cudaMemcpy(&d_data, &h_data, sizeof(MyStruct) * 1, cudaMemcpyHostToDevice));
    checkCuda(cudaMemcpy(&(d_data->a), &(h_data->a), sizeof(int) * 32, cudaMemcpyHostToDevice)); 


    structOperation<<<1,32>>>(d_data);


    checkCuda(cudaMemcpy(&out_data, &d_data, sizeof(myStruct) * 1, cudaMemcpyDeviceToHost));
  //cudaMemcpy(&(out_data->a), &(d_data->a), sizeof(int) * d_data->b, cudaMemcpyDeviceToHost); 

    printf("\nDataElements : ");
    for(int i = 0; i<32; i++){
        printf("    %d",out_data->a[i]);
    }
    printf("\n");
}

I am getting 'Segmentation Fault' as the result of execution. I guess I am operating the structure incorrectly. What is the proper way to implement?

like image 641
sandeep.ganage Avatar asked Dec 04 '25 14:12

sandeep.ganage


1 Answers

There are several invalid memory access in the provided code.

  1. Accessing device memory (allocated using cudaMalloc) from host like d_data->a will cause undefined behavior (segmentation fault etc.).
  2. cudaMemcpy takes pointers as arguments, not address of pointer. So cudaMemcpy(&d_data, &h_data... should be replaced with cudaMemcpy(d_data, h_data....

Allocating a device object with a device pointer as a member is a bit tricky. It can be achieved as follows:

  1. Allocate a temporary host object (MyStruct temp).
  2. Allocate device memory to the member we want on device (cudaMalloc(&temp.a, bytes)).
  3. Allocate device object (cudaMalloc(&d_data, sizeof(MyStruct)).
  4. Copy temporary host object to the device object (cudaMemcpy(d_data, &temp, sizeof(MyStruct), cudaMemcpyHostToDevice)).

Keep in mind that when you modify the contents of d_data->a on the device, temp.a will also be modified because they are actually pointing to same memory location on device.

Your final main function will look something like this:

int main(){
    MyStruct *h_data, *d_data, *out_data;

    size_t structSize = sizeof(MyStruct);
    size_t intSize = sizeof(int);


    h_data = (MyStruct *) malloc(structSize * 1);
    h_data->b = 32;
    h_data->a = (int *)malloc(intSize * h_data->b);

    out_data = (MyStruct *) malloc(structSize * 1);
    out_data->b = 32;
    out_data->a = (int *)malloc(intSize * out_data->b);

    for(int i = 0; i<32; i++){
        h_data->a[i] = i;   
    }

    //Create temporary MyStruct object on host and allocate memory to its member "a" on device
    MyStruct temp;
    temp.b = h_data->b;
    checkCuda(cudaMalloc(&temp.a, 32 * sizeof(int)));

    //Copy host data to temp.a
    checkCuda(cudaMemcpy(temp.a, h_data->a, 32 * sizeof(int), cudaMemcpyHostToDevice));

    //Memory allocation for the device MyStruct
    checkCuda(cudaMalloc(&d_data, sizeof(MyStruct) * 1));
    //Copy actual object to device
    checkCuda(cudaMemcpy(d_data, &temp, sizeof(MyStruct) * 1, cudaMemcpyHostToDevice));


    structOperation<<<1,32>>>(d_data);

    //temp.a will be updated after kernel launch
    checkCuda(cudaMemcpy(out_data->a, temp.a, 32 * sizeof(int), cudaMemcpyDeviceToHost)); 

    printf("\nDataElements : ");
    for(int i = 0; i<32; i++)
    {
        printf("    %d",out_data->a[i]);
    }
    printf("\n");

    checkCuda(cudaFree(temp.a));
    checkCuda(cudaFree(d_data));

    free(h_data->a);
    free(out_data->a);
    free(h_data); 
    free(out_data);
}
like image 93
sgarizvi Avatar answered Dec 07 '25 15:12

sgarizvi



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