Set default value and type for parameter [duplicate]

Question

How can I do something like this:

def profile(request, pk=0 : int):
    #to do

I need pk to be int (without converting in function).

Like this:

def profile(request, pk: int):

If pk empty - set value to 0 and type to int.

Answer 1

You can't really specify it directly in the argument field, but you can convert it right after the function declaration:

def profile(request, pk=0):
    pk = int(pk)
    #to do

It will throw an error if the passed value for pk cannot be converted to an int

EDIT: I spoke too soon, apparently you can do exactly as you did, just change things around:

def profile(request, pk: int = 0):
    #to do

BTW: I just did a quick research for "specify type of argument python". Please try to research easy things like so first before asking a question, you'll get an answer quicker :)