I have this piece of code
import scala.util.Try
val t: Try[Unit] = Try(Try(1))
and 2 questions:
Try[Try[Int]]
match with
Try[Unit]
? Is it because Scala chooses the return type for block
Try(1)
to be Unit
to match with the desired type?Try
? Says I have a Try[A]
, how do I know if A
is another Try[_]
?You are basically forcing compiler to assign Try
as Unit
.
For exmple doSomething
method below is supposed to return Int
as that is last statement, but return type Unit
is forcing it to return ()
.
scala> def doSomething: Unit = 1 + 1
doSomething: Unit
In your example val t: Try[Unit] = Try(Try(1 / 0))
, you asking compiler to treat inner Try(1 / 0)
as Unit
; which means
scala> val innerTry: Unit = Try(1 / 0)
innerTry: Unit = ()
Which means even if Try
fails, its Unit
which is always Success
for another Try
that you have.
scala> val t: Try[Unit] = Try(someOperation)
t: scala.util.Try[Unit] = Success(())
Better remove the specific type you are providing and let the compiler figure it out,
scala> val t = Try(Try(1 / 0))
t: scala.util.Try[scala.util.Try[Int]] = Success(Failure(java.lang.ArithmeticException: / by zero))
Also read: Scala: Why can I convert Int to Unit?
final abstract class Unit private extends AnyVal {
// Provide a more specific return type for Scaladoc
override def getClass(): Class[Unit] = ???
}
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