I have a folder called TEST with inside :
The bash file is :
#!/bin/bash
# Run the python script
python script.py
If I run the bash file like this :
./TEST/script.sh
I have the following error :
python: can't open file 'script.py': [Errno 2] No such file or directory
How could I do, to tell my script.sh to look in the directory (which may change) and to allow me to run it for inside the TEST directory ?
Tricky, my python file run a sqlite database and I have the same problem when calling the script from outside the folder, it didn't look inside the folder to find the database!
You are able to run the script directly by adding this line to the top of your python file:
#!/usr/bin/env python
and then making the file executable:
$ chmod +x script.py
With this, you can run the script directly with ./TEST/script.py
This works to get the path of the script, and then pass that to python.
#!/bin/sh
SCRIPTPATH="$( cd "$(dirname "$0")" ; pwd -P )"
python "$SCRIPTPATH/script.py"
You mentioned having this problem with accessing a sqlite DB in the same folder, if you are running this from a script to solve this problem, it will not work. I imagine this question may be of use to you for that problem: How do I get the path of a the Python script I am running in?
You could use $0 which is the name of the currently executing program, as invoked, combined with dirname which provides the directory component of a file path, to determine the path (absolute or relative) that the shell script was invoked under. Then, you can apply it to the python invocation.
This example worked for me:
$ t/t.sh
Hello, world!
$ cat t/t.sh
#!/bin/bash
python "$(dirname $0)/t.py"
Take it a step farther and change your current working directory which will also be inherited by python, thus helping it to find its database:
$ t/t.sh; cat t/t.sh ; cat t/t.py ; cat t/message.txt
hello, world!
#!/bin/bash
cd "$(dirname $0)"
python t.py
with(open('message.txt')) as msgf:
print(msgf.read())
hello, world!
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