Using $('div#top_container').html(), I get the following as an example:
<div class="top" id="top_container">
<div class="example">First</div>
<div class="example">Second</div>
</div>
giving...
<div class="example">First</div>
<div class="example">Second</div>
Here, using .replace(), I want to replace <div class="example"> with *%^% (random set of characters) and remove </div>:
var content = $('div#top_container').html();
var clean_1 = content.replace('<div class="example">','*%^%'); //add $*!#$
var clean_2 = clean_1.replace('</div>',' '); //remove </div>
giving...
console.log(clean_2); --> *%^%First*%^%Second
Now, the number of example div elements can vary and I need to first find out how to target them all. Also is there a cleaner way to target both <div class="example"> and </div> at the same time?
EDIT:
I am not looking to change the html itself, but rather have the edited version as a variable that I can do stuff with (such as send it to php via ajax).
How would I do this?
Use replaceWith() method with a callback and generate prefered text string by getting text content using text() method.
$('div.example').replaceWith(function(v) {
return '%^%' + $(this).text();
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<div class="example">First</div>
<div class="example">Second</div>
</div>
UPDATE: If you don't want to update the original element then use clone() and do the remaining thinks on the cloned element.
var res = $('#parent')
// clone element
.clone()
// get element with `example` class
.find('.example')
// update content
.replaceWith(function(v) {
return '%^%' + $(this).text();
})
// back to previos selector and get html content
.end().html();
console.log(res)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="parent">
<div class="example">First</div>
<div class="example">Second</div>
</div>
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