Renaming the column headers from an iterative list of ranges using Lambda

Question

opvalue_time.columns = opvalue_time.rename(lambda x: "Vol_" + x for x in range(4,80,1))

i already have a dataset with 80 columns , need to update the column headers as Vol_4, ....Vol_80. Currently the columns are 0(no headers)

Answer 1

I don't think the rename method can directly process a generator expression. Instead, you can use a dictionary comprehension to create a mapping of old column names to new ones, or directly assign a new list of column names to opvalue_time.columns. You could try this instead:

opvalue_time.columns = ["Vol_" + str(x) for x in range(4, 80)]

This assumes your DataFrame initially has 76 columns, matching the range specified (you may need to adjust the range as necessary)