Regular expression to find a series of uppercase words in a string

Question

text = "This is a TEXT CONTAINING UPPER CASE WORDS and lower case words. This is a SECOND SENTENCE."

pattern = '[A-Z]+[A-Z]+[A-Z]*[\s]+'

re.findall(pattern, text) gives an output -->

['TEXT ', 'CONTAINING ', 'UPPER ', 'CASE ', 'WORDS ', 'SECOND ', 'SENTENCE ']

However, I want an output something like this -->

['TEXT CONTAINING UPPER CASE WORDS', 'SECOND SENTENCE']

Answer 1

You may use this regex:

\b[A-Z]+(?:\s+[A-Z]+)*\b

RegEx Demo

RegEx Details:

• \b: Word boundary
• [A-Z]+: Match a word comprising only uppercase letters
• (?:\s+[A-Z]+)*: Match 1+ whitespace followed by another word with uppercase letters. Match this group 0 or more times
• \b: Word boundary

Code:

>>> s = 'This is a TEXT CONTAINING UPPER CASE WORDS and lower case words. This is a SECOND SENTENCE';
>>> print (re.findall(r'\b[A-Z]+(?:\s+[A-Z]+)*\b', s))
['TEXT CONTAINING UPPER CASE WORDS', 'SECOND SENTENCE']