Python Pyinstaller ERRNO 22 Invalid Argument

Question

I am trying to use pyinstaller to make my python code more user-friendly, and until yesterday, it was working. When I ran it today I got the error below:

C:\Users\user\Desktop\PythonProjects38>pyinstaller --onefile TransmittalEXE.py
83 INFO: PyInstaller: 4.0
83 INFO: Python: 3.8.5
83 INFO: Platform: Windows-10-10.0.18362-SP0
84 INFO: wrote C:\Users\user\Desktop\PythonProjects38\TransmittalEXE.spec
...
31623 INFO: checking PKG
31623 INFO: Building PKG because PKG-00.toc is non existent
31628 INFO: Building PKG (CArchive) PKG-00.pkg
41852 INFO: Building PKG (CArchive) PKG-00.pkg completed successfully.
41915 INFO: Bootloader c:\users\user\desktop\pythonprojects38\venv\lib\site-packages\PyInstaller\bootloader\Windows-32bit\run.exe
41915 INFO: checking EXE
41917 INFO: Building EXE because EXE-00.toc is non existent
41921 INFO: Building EXE from EXE-00.toc
41927 INFO: Updating manifest in C:\Users\user\Desktop\PythonProjects38\build\TransmittalEXE\run.exe.d66z9a0v
42037 INFO: Updating resource type 24 name 1 language 0
42050 INFO: Appending archive to EXE C:\Users\user\Desktop\PythonProjects38\dist\TransmittalEXE.exe
Traceback (most recent call last):
  File "C:\Users\user\AppData\Local\Programs\Python\Python38-32\lib\runpy.py", line 194, in _run_module_as_main
    return _run_code(code, main_globals, None,
  File "C:\Users\user\AppData\Local\Programs\Python\Python38-32\lib\runpy.py", line 87, in _run_code
    exec(code, run_globals)
  File "C:\Users\user\Desktop\PythonProjects38\pyinstaller.exe\__main__.py", line 7, in <module>
  File "c:\users\user\desktop\pythonprojects38\venv\lib\site-packages\PyInstaller\__main__.py", line 114, in run
    run_build(pyi_config, spec_file, **vars(args))
  File "c:\users\user\desktop\pythonprojects38\venv\lib\site-packages\PyInstaller\__main__.py", line 65, in run_build
    PyInstaller.building.build_main.main(pyi_config, spec_file, **kwargs)
  File "c:\users\user\desktop\pythonprojects38\venv\lib\site-packages\PyInstaller\building\build_main.py", line 720, in main
    build(specfile, kw.get('distpath'), kw.get('workpath'), kw.get('clean_build'))
  File "c:\users\user\desktop\pythonprojects38\venv\lib\site-packages\PyInstaller\building\build_main.py", line 667, in build
    exec(code, spec_namespace)
  File "C:\Users\user\Desktop\PythonProjects38\TransmittalEXE.spec", line 20, in <module>
    exe = EXE(pyz,
  File "c:\users\user\desktop\pythonprojects38\venv\lib\site-packages\PyInstaller\building\api.py", line 446, in __init__
    self.__postinit__()
  File "c:\users\user\desktop\pythonprojects38\venv\lib\site-packages\PyInstaller\building\datastruct.py", line 160, in __postinit__
    self.assemble()
  File "c:\users\user\desktop\pythonprojects38\venv\lib\site-packages\PyInstaller\building\api.py", line 622, in assemble
    with open(exe, 'rb') as infh:
OSError: [Errno 22] Invalid argument: 'C:\\Users\\user\\Desktop\\PythonProjects38\\build\\TransmittalEXE\\run.exe.d66z9a0v'

For more reference I've tried uninstalling and reinstalling pyinstaller and pywin32 to no avail. My command prompt entry is pyinstaller --onefile TransmittalEXE.py.

Has anyone else encountered this issue? I've seen similar on this forum, but not this exact issue.

Answer 1

I had the same problem and I was able to fix it by going to Windows anti-virus protection option and adding the folder my script was as an exception.

Go to Start > Settings > Update & Security >Windows Security , and then select Virus & threat protection. Under Virus & threat protection settings, select Manage settings. Add the folder with your desired script as an exception.