Given a generic type T in C#, I wonder how to acquire type Q, which is equal to T? for non-nullable T, and T for already nullable T.
The question arose from real code. I want to unify access to parameters passed through query string in my ASP.NET application. And I want to specify a default value of the same type, but ensure null can be passed as a default value.
public static T FetchValue<T>(
string name,
<T? for non-nullable, T otherwise> default_value = null) // How to write this?
{
var page = HttpContext.Current.Handler as Page;
string str = page.Request.QueryString[name];
if (str == null)
{
if (default_value == null)
{
throw new HttpRequestValidationException("A " + name + " must be specified.");
}
else
{
return default_value;
}
}
return (T)Convert.ChangeType(str, typeof(T));
}
Currently I'm forced having two overloads of the FetchValue - one without default value, and one with it:
public static T FetchValue<T>(string name);
public static T FetchValue<T>(string name, T default_value);
It works fine, but I wonder whether it is possible to merge both functions like this.
In C++ I would use type-traits, like PromoteNullable<T>::type with two specializations of PromoteNullable for both nullable and non-nullable types. But what about C#?
Doesn't directly answer the question as posed, but I'd write this:
public static T FetchValue<T>(string name)
{
T value;
if (TryFetchValue(name, out value))
return value;
throw new HttpRequestValidationException("A " + name + " must be specified.");
}
public static T FetchValue<T>(string name, T default_value)
{
T value;
if (TryFetchValue(name, out value))
return value;
return default_value;
}
private static bool TryFetchValue<T>(
string name,
out T value)
{
var page = HttpContext.Current.Handler as Page;
string str = page.Request.QueryString[name];
if (str == null)
{
value = default(T);
return false;
}
value = (T)Convert.ChangeType(str, typeof(T));
return true;
}
So the bulk of the code exists only once - and you can even now actually have the calling code choose to have null as a default value, if it so chooses.
Even if you could create the parameter declaration you wanted, this line would still be an issue:
return default_value;
If it turned out that default_value was a T? rather than a T, then the above code doesn't work. Even if you do a cast:
return (T)default_value;
there's still an issue - that to cast from T? to T, the compiler actually has to insert a call to obtain the Value property of the nullable. But that call wouldn't be valid if the type of default_value was just T.
In C# Generics, the compiler has to create one piece of IL for the method. There's no way to insert an optional piece of code that may access Value.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With