preg_match lazy?

Question

Hey guys I'm trying to strip out the last _1.jpg if it exists in my expression, but I am having some trouble

Scenarios are like follows.

image_name_1.jpg (should be image_name.jpg)

image_name_1_1.jpg (should be image_name_1.jpg)

I came up with this, but it seems to be returning null

$pic = ($pic[strlen]-6 == '_') ? preg_replace('/*.\_[0-9]/', '.jpg', $pic) : $pic;

What's wrong with my formula? Could someone help?

Answer 1

*. makes here truble. You can use *.? - the ? mean lazy quantification.

But your expression havent to pattern whole input string, only target - see ohaal's answer.

Answer 2

This should do it:

preg_replace('/_\d\.jpg$/', '.jpg', $pic);