PHP Array Intersect dont include empty arrays

Question

I have 4 arrays, which are going to be different every time I run my code. Sometimes, maybe empty. I am using array_intersect to get the common value from the set of arrays and if any one of the array is empty it returns me an empty array. I want array_intersect to ignore empty array's.

Example:

$array1 = array('441', '442', '443');
$array2 = array('441', '443');
$array3 = array('441', '442',);
$array4 = array();

var_dump(array_intersect($array1, $array2, $array3, $array4));

// Returns
array('');

// Required
array('441');

How do I make it ignore $array4 and give an output of 441

Answer 1

If you store your arrays as an array you can do this:

<?php
// create array of arrays
$array[] = array('441', '442', '443');
$array[] = array('441', '443');
$array[] = array('441', '442');
$array[] = array();

// filter out empty array
$array = array_filter($array);

// pass in array (inline argument unpacking PHP > 5.6)
print_r(array_intersect(...$array));

Array
(
    [0] => 441
)

https://3v4l.org/MD3r2

Answer 2

$tempArray = [];
if (count($g_arr) >0) $tempArray[] = $g_arr;
if (count($c_arr) >0) $tempArray[] = $c_arr;
if (count($k_arr) >0) $tempArray[] = $k_arr;
if (count($m_arr) >0) $tempArray[] = $m_arr;
if (count($p_arr) >0) $tempArray[] = $p_arr;

$intersect = call_user_func_array('array_intersect', $tempArray);