Operand of * must be a pointer

Question

This is my script

#include <stdio.h>
#define PI 3.14;

int main(void){
    double hasil, input;
    printf("Enter a positive number : ");
    scanf("%lf",&input);
    hasil = PI * input;
    printf("\nThe result is : %lf",hasil);
    getchar();
    return 0;
}

I get error * must be a pointer? What's it? I mean '*' sign is to multiply number....

Answer 1

Your PI constant contains a semicolon which will terminate the expression prematurely;

#define PI 3.14;

...will result in the expression;

hasil = 3.14; * input;

It should be defined as only;

#define PI 3.14