I have tried using August William's solution to this issue, but that also didn't work. I am not switching workbook types, i.e. .xlsm to .xlsx, which appears to be a separate issue. I have looked through Openpyxl's Manual trying to find maybe a bug report or bug fix, but to no avail. The below is my very simple code. Following that is the python error message which results in a workbook being created, but it is corrupted and fails to load. Any help is appreciated. -Thanks!!
from openpyxl import Workbook
dashbrd = Workbook()
fp = dashbrd.active
fp.title = 'Sheet Name Goes Here'
fp['A1'] = 'Header'
fp['B1'] = '2nd Header'
fp['C1'] = '3rd Header'
fp['D1'] = '4th Header'
fp['E1'] = '5th Header'
fp['F1'] = 'You get the idea'
fp['G1'] = 'Another Header'
fp['H1'] = 'Blah blah blah'
fp['I1'] = 'Yadda yadda yadda'
dashbrd.save("S:\\folder1\\folder2\\folder3\\MyBook.xlsx")
**************************************************************************************
Traceback (most recent call last):
File "C:\Users\NotaDirtyUser\Documents\Scripts\HeaderTest.py", line 26, in <module>
dashbrd.save("S:\\folder1\\folder2\\folder3\\MyBook.xlsx")
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\workbook\workbook.py", line 408, in save
save_workbook(self, filename)
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\writer\excel.py", line 293, in save_workbook
writer.save()
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\writer\excel.py", line 275, in save
self.write_data()
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\writer\excel.py", line 75, in write_data
self._write_worksheets()
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\writer\excel.py", line 215, in _write_worksheets
self.write_worksheet(ws)
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\writer\excel.py", line 200, in write_worksheet
writer.write()
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\worksheet\_writer.py", line 354, in write
self.write_top()
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\worksheet\_writer.py", line 98, in write_top
self.write_properties()
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\worksheet\_writer.py", line 60, in write_properties
self.xf.send(props.to_tree())
File "C:\ProgramData\Anaconda3\lib\site-packages\openpyxl\worksheet\_writer.py", line 294, in get_stream
xf.write(el)
File "src/lxml/serializer.pxi", line 1652, in lxml.etree._IncrementalFileWriter.write
TypeError: got invalid input value of type <class 'xml.etree.ElementTree.Element'>, expected string or Element
Like I said above , yesterday I had the same problem ..I found the solution in this link:
https://python-forum.io/Thread-Need-help-in-understanding-this-particular-Traceback-TypeError
In reference to this error : TypeError: got invalid input value of type , expected string or Element
In summary the solution was to install openpyxl to another version :
pip uninstall openpyxl
pip install openpyxl==3.0.1
I can't find a good reference, but I recall having stumbled upon the same, and the solution was to use the older format (.xls, which is a completely different format) instead. Seems like a generic problem of openpyxl that wasn't resolved at the moment.
A working way to append to .xlsx (works for me):
from openpyxl import load_workbook
writer = pd.ExcelWriter(filename, engine='openpyxl')
try:
# try to open an existing workbook
writer.book = load_workbook(filename)
# get the last row in the existing Excel sheet
# if it was not specified explicitly
if startrow is None and sheet_name in writer.book.sheetnames:
startrow = writer.book[sheet_name].max_row
# truncate sheet
if truncate_sheet and sheet_name in writer.book.sheetnames:
# index of [sheet_name] sheet
idx = writer.book.sheetnames.index(sheet_name)
# remove [sheet_name]
writer.book.remove(writer.book.worksheets[idx])
# create an empty sheet [sheet_name] using old index
writer.book.create_sheet(sheet_name, idx)
# copy existing sheets
writer.sheets = {ws.title: ws for ws in writer.book.worksheets}
except FileNotFoundError:
# file does not exist yet, we will create it
pass
if startrow is None:
startrow = 0
# write out the new sheet
df.to_excel(writer, sheet_name, startrow=startrow, **to_excel_kwargs)
# save the workbook
writer.save()
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