Matching incremental digits in numbers

Question

After googling many days about the issue, finally I am posting this question here and hoping to get it solved by experts here; I am looking for the regex pattern that can match incremental back references. Let me explain:

For number 9422512322, the pattern (\d)\1 will match 22 two times, and I want the pattern (something like (\d)\1+1) that matches 12 (second digit is equal to first digit + 1)

In short the pattern should match all occurrence like 12, 23, 34, 45, 56, etc... There is no replacement, just matches required.

Answer 1

What about something like this?

/01|12|23|34|45|56|67|78|89/

It isn't sexy but it gets the job done.

Answer 2

You can use this regex:

(?:0(?=1)|1(?=2)|2(?=3)|3(?=4)|4(?=5)|5(?=6)|6(?=7)|7(?=8)|8(?=9))+.

This will match:

• Any 0s which are followed by 1s, or
• Any 1s which are followed by 2s, or
• Any 2s which are followed by 3s, ...

Multiple times +, then match the corresponding character ..

Here is a regex demo, and the match is:

12345555567877785