Julia: Is there a way to return an iterator of each value of an index?

Question

Consider m = [1 2 3; 4 5 6; 7 8 9]

for idx in eachindex(m)
  println(idx)
end

I was expecting it to print (1, 1) (2, 1), (3, 1) .... (1, 3), (2, 3), (3, 3) but it prints 1, 2, ..., 9.

What's the most elegant way to loop through all the indices of a multidimensional array?

Answer 1

What about

julia> for i in CartesianIndices(m)
           println(Tuple(i))
       end
(1, 1)
(2, 1)
(3, 1)
(1, 2)
(2, 2)
(3, 2)
(1, 3)
(2, 3)
(3, 3)

(You can access the tuple of subindices of i::CartseianIndex with Tuple(i).)