Jquery select all Input except type hidden

Question

I am selecting all inputs in jquery, like this:

$('input').each(function() {
...
});

But is it possible to create an exception like saying select all inputs with the exception of input type hidden.

I know that I could select input with the specific types I need but that does not look that good I think

Edit: sorry made the wrong example, I mean something like this:

document.forms["product"].getElementsByTagName("input");

with the exception of hidden

Answer 1

Try this : you can make use of :not with [type="hidden"]

$(function(){
  $('input:not([type="hidden"])').each(function(){
    alert($(this).val());
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input value="1">
<input type="radio" value="2">
<input type="hidden" value="3">
<input type="checkbox" value="4">

Answer 2

There are various method to use. I would prefer to use:

$('input:visible').each();

Notice: :visible does not select the input with the type="hidden".

Or you may use a little longer method:

$('input:not([type="hidden"]').each();

Or,

$('input').not('[type="hidden"]').each();

API References: visible-selector, not-selector, not