JAXB or Jackson for xml unmarshalling?

Question

Receiving an XML response, there are two main solutions decoding xml to a DTO object. Why should one prefer JAXB over jackson, or the other way around?

JAXB:

Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
XMLStreamReader reader = XMLInputFactory.newInstance().createXMLStreamReader(new StringReader(xmlString));
unmarshaller.unmarshal(reader, DtoObject.class);

Jackson:

mapper = new ObjectMapper() / new XmlMapper();
mapper.readValue(xmlString, DtoObjectc.class);

Answer 1

In my opinion, I will use JAXB, the following reason.

1. It is quite matured and part of JDK.
2. I do not need third party additional library to use
3. Jackson2 XML transformation is new as compared to JAXB which is in the industry for a quite long time and there are lot of community for it.

However I am not saying that which is good or bad. Again it is a choice to the developer to use.