Javascript remove object from array if object contains string

Question

I have an array of objects looking similar to this

[{ id: "11", name: "Car", symbol: "CA" }
,{ id: "13", name: "Cycle", symbol: "CY" }
,{ id: "15", name: "Train", symbol: "TA" }
,{ id: "3", name: "Ufo", symbol: "UF" }]

Lets assume i have this string Car how do i search through the array of objects to find which object if any contains that particular string in the name key and then remove that object from the array of objects?

This is what i got so far (Basically nothing because i dont know what to do from here)

function remove_obj_from_array_of_objs(str, array_of_objs){

}

Answer 1

You can use filter() and includes() methods for this.

const data = [{ id: "11", name: "Car", symbol: "CA" },{ id: "13", name: "Cycle", symbol: "CY" },{ id: "15", name: "Train", symbol: "TA" },{ id: "3", name: "Ufo", symbol: "UF" }]

const result = data.filter(({name}) => !name.includes('Car'))
console.log(result)

Answer 2

Try Array's filter() like the following:

var carArr = [{ id: "11", name: "Car", symbol: "CA" }
,{ id: "13", name: "Cycle", symbol: "CY" }
,{ id: "15", name: "Train", symbol: "TA" }
,{ id: "3", name: "Ufo", symbol: "UF" }];

var notIncludesCar = carArr.filter(item => !item.name.includes("Car"));

console.log(notIncludesCar);