I am trying to encode/decode a ByteArray to String, but input/output are not matching. Am I doing something wrong?
System.out.println(org.apache.commons.codec.binary.Hex.encodeHexString(by));
String s = new String(by, Charsets.UTF_8);
System.out.println(org.apache.commons.codec.binary.Hex.encodeHexString(s.getBytes(Charsets.UTF_8)));
The output is:
130021000061f8f0001a
130021000061efbfbd
Complete code:
String[] arr = {"13", "00", "21", "00", "00", "61", "F8", "F0", "00", "1A"};
byte[] by = new byte[arr.length];
for (int i = 0; i < arr.length; i++) {
by[i] = (byte)(Integer.parseInt(arr[i],16) & 0xff);
}
System.out.println(org.apache.commons.codec.binary.Hex.encodeHexString(by));
String s = new String(by, Charsets.UTF_8);
System.out.println(org.apache.commons.codec.binary.Hex.encodeHexString(s.getBytes(Charsets.UTF_8)));
The problem here is that f8f0001a isn't a valid UTF-8 byte sequence.
First of all, the f8 opening byte denotes a 5 byte sequence and you've only got four. Secondly, f8 can only be followed by a byte of 8x, 9x, ax or bx form.
Therefore it gets replaced with a unicode replacement character (U+FFFD), whose byte sequence in UTF-8 is efbfbd.
And there (rightly) is no guarantee that the conversion of an invalid byte sequence to and from a string will result in the same byte sequence. (Note that even with two, seemingly identical strings, you might get different bytes representing them in Unicode, see Unicode equivalence. )
The moral of the story is: if you want to represent bytes, don't convert them to characters, and if you want to represent text, don't use byte arrays.
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