I'm relatively new to Java programming and I've just started learning recursion, but I can't seem to figure out how this method works in my head.
private static int mystery(int w) {
{
if (w < 0) return 0;
int x = mystery (w-2);
return w - x;
}
}
Whenever a variable like 100 is put in, it outputs 50. When 200 is input, it outputs 100. When 2 is input, it outputs 2. When 25 is input, 13 is output. I'm not sure how this method works, and I'm trying to wrap my head around it.
The way I currently view it, if you put in 100, it'll bypass the first return statement since it is greater than 0. when it gets to the second line, it'll do 100-2, which brings in 98, then goes to the third line and does 100 - 98 = 2. Which is then returned to the original call.
I know I'm messing up on the second line of the method where the mystery (w-2) is. I assume it would bring back the result of w-2 to the beginning of the method again, and it would continue to do the method over and over again until w is smaller than 0, which should output 0 again regardless of the answer. But that's not what happens, and I don't know why.
Can anyone explain what is going on here?
What you are missing is that on the second line it doesn't just do w - 2, but calls itself with w - 2. It doesn't go further until the call returns. And the second call calls itself if w isn't < 0 and so on until you reach value lower than 0 and then return. The execution will go like this, if you visualize it:
mystery(10)
> skip first line
> x = mystery(8)
> skip first line
> x = mystery(6)
> skip first line
> x = mystery(4)
> skip first line
> x = mystery(2)
> skip first line
> x = mystery(0)
> skip first line
> x = mystery(-2)
> return 0
> return 0 - 0 (0)
> return 2 - 0 (2)
> return 4 - 2 (2)
> return 6 - 2 (4)
> return 8 - 4 (4)
> return 10 - 4 (6)
With example of w = 10. I hope you understand it better now.
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