is there any named regular expression capture for grep?

Question

i'd like to know if its possible to get named regular expression with grep -P(linux bash) from a non formatted string? well.. from any string

For example: John Smith www.website.com [email protected] jan-01-2001 to capture as

$name
$website
$email
$date

but it seems I cant pass any variables from output?

echo "www.website.com" | grep -Po '^(www\.)?(?<domain>.+)$' | echo $domain

has no output

Answer 1

no. grep is a process. you are talking about environment propagation from child to parent. that's forbidden.

instead, you can do

DATA=($your_line)

then take name=DATA[0] so and forth.

or another way using awk:

eval "`echo $your_line | awk '
    function escape(s)
    {
        gsub(/'\''/,"'\''\"'\''\"'\''", s);
        s = "'\''"s"'\''";
        return s;
    }
    { 
        print "name="escape($1);
        print "family_name="escape($2);
        print "website="escape($3);
        print "email="escape($4);
        print "date="escape($5);
    }'`"

the sense here is to propagate the info via stdout and eval it in the parent environment.

notice that, here, escape function will escape any string correctly such that nothing will be interpreted wrongly(like the evil of quotes).

following is the output from my jessie:

name='John'
family_name='Smith'
website='www.website.com'
email='[email protected]'
date='jan-01-2001'

if the family name is O'Reilly, the eval result will still be correct:

name='John'
family_name='O'"'"'Reilly'
website='www.website.com'
email='[email protected]'
date='jan-01-2001'