I'd like to decode this string: X-OVH-SPAMCAUSE: gggruggvucftvghtrhhoucdtuddrfeelgedrvdduucetufdoteggodetrfdotffvucfrrhhofhhilhgvmecuqfggjfenuceurghilhhouhhtmecufedttdenucgohfhorhgsihguuggvnhfjughrucdlhedttddm
Has someone a tool or something who could do this ?
Thanks.
Starting from lkraider's great answer, I improved the accuracy. It turns out that the offset characters (c..g) are alternatingly appended and prepended. So instead of just checking if one of them is in the pair, it is necessary to differentiate between, e.g., fh and hf, by keeping track of even or odd pairs.
def decode(msg):
text = ""
for i in range(0, len(msg), 2):
text += unrot(msg[i: i + 2], i // 2) # add position as extra parameter
return text
def unrot(pair, pos, key=ord('x')):
if pos % 2 == 0: # "even" position => 2nd char is offset
pair = pair[1] + pair[0] # swap letters in pair
offset = (ord('g') - ord(pair[0])) * 16 # treat 1st char as offset
return chr(sum(ord(c) for c in pair) - key - offset) # map to original character
print(decode('gggruggvucftvghtrhho'))
https://gist.github.com/DoubleYouEl/e3de97293ce3d5452b3be7a336a06ad7
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