iOS: How to get the selected UIMenuItem from UIMenuController

Question

I am trying to use UIMenuCnotroller to show a list of dynamically generated items, they share the same action method, and so I need to know which item is selected in the single action method.

However, in the action method - (void)menuItemAction:(id)sender;the sender is actually the UIMenuController object, and I didn't find any method of UIMenuController can tell me which menuitem is selected.

One solution I can think of is to dynamically generate different action selectors for different items, and do some tricks in forwardInvocation

But is there any easier way?

Answer 1

You can use UIMenuCnotroller like: 1) creation:

UIMenuController *menuController = [UIMenuController sharedMenuController];
        UIMenuItem *open = [[UIMenuItem alloc] initWithTitle:@"Open" action:@selector(open:)];
        UIMenuItem *reDownload = [[UIMenuItem alloc] initWithTitle:@"Re-Download" action:@selector(reDownload:)];

        [menuController setMenuItems:[NSArray arrayWithObjects:open, reDownload, nil]];
        [menuController setTargetRect:cell.frame inView:self.view];
        [menuController setMenuVisible:YES animated:YES];

        [open release];
        [reDownload release];

2) To catch actions should implement next methods:

- (BOOL) canPerformAction:(SEL)selector withSender:(id) sender 
{
    if (selector == @selector(open:))
    {
        return YES;
    }

    if (selector == @selector(reDownload:))
    {
        return YES;
    }

    return NO;
}

- (BOOL) canBecomeFirstResponder 
{
    return YES;
}

3) And realization of yours methods:

- (void) open:(id) sender 
{
    [self doSomething];
}

- (void) reDownload:(id) sender 
{
[self doSomething];
}

Hope, this helps.