Ill formed code snippets

Question

can somebody please tell me the difference between the following two code snippets:

//Code snippet A: Compiles fine
int main()
{
    if(int i = 2)
    {
        i = 2 + 3;
    }
    else
    {
        i = 0;
    }
}

//Code Snippet B: Doesn't compile :(
int main()
{
    if((int i = 2))
    {
        i = 2 + 3;
    }
    else
    {
        i = 0;
    }
}

If you notice the diff is just an extra parenthesis at if statement. I am using g++ compiler.Error is "expected primary-expression before âintâ"

Answer 1

Section 6.4 of the C++ standard (draft n2914 of c++0x) has this to say about the format of if statements:

Selection statements choose one of several flows of control.
   selection-statement:
      if ( condition ) statement
      if ( condition ) statement else statement
      switch ( condition ) statement
   condition:
      expression
      type-specifier-seq attribute-specifieropt declarator = initializer-clause
      type-specifier-seq attribute-specifieropt declarator braced-init-list

That bit at the end means a condition can be either an expression or a decalarator-type construct.

And the minute the parser hits that second parenthesis, it becomes an expression, so no declarations allowed, I'm afraid.

The snippet:

if (int i = 2) { ... } else { ... }

is perfectly valid C++ in which the if section defines an integer i for the duration of the if/else and sets it to 2. It then uses that 2 as the input to the if (2 is always true, being non-zero).

The snippet if((int i = 2)) is no different syntactically to int x = (int i = 2;); if (x) which is not valid C++.