How to sort a list based on the summation of second elements of tuple within a list?

Question

My concern involves one of my variables which have tuples within a list as follows.

test = [(['a','b','c'],[3,2,5]),(['d','e','f'],[1,5,6]),(['g','h','j'],[1,2,4])]

I am trying to get the summation of the second tuple element of the lists for example [3,2,5] and sort them based on that summation. so the result of that summation should be.

result1 = [(['a','b','c'],[10]),(['d','e','f'],[12]),(['g','h','j'],[7])]

then my intended final result should be sorted in descending order.

result = [['d','e','f'],['a','b','c'],['g','h','j']]

Answer 1

An elegant one liner:

result = [a for a, b in sorted(test, key = lambda x : sum(x[1]), reverse=True)]

sorted returns a sorted list using the passed iterable, in this case test

key defines the basis for sorting. Here it's a lambda expression which takes the tuple x and returns the sum of the 2nd part of the tuple sum(x[1])

reverse is set so that sorting is in descending order

Finally we use a list comprehension to get rid of the numeric part b and keep only the alphabets a