How to run a gulp task from another task?

Question

I am aware of the ability to declare dependencies that will run before the task, e.g.

gulp.task('a', () => {}); gulp.task('b', () => {}); gulp.task('c', ['a', 'c'], () => {}); 

Tasks 'a' and 'b' will be run every time after task 'c' is called and before task 'c' is executed.

However, how do I programmatically call an arbitrary task from within a gulp.task?

Answer 1

I did it using gulp.start(); like this:

gulp.task('test1', function(){   gulp.start('test2'); })  gulp.task('test2', function(){   // do something }) 

I was using gulp 3.9.1 if it matters. Looks like gulp.start() may be removed or deprecated; but it hasn't happened yet.

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Update If I were to break things out into separate functions, as Novellizator suggested, it would be something like this:

function doSomething(){   // do something }  gulp.task('test1', function(){   doSomething(); })  gulp.task('test2', function(){   doSomething(); }) 

It is simple and avoids the use of gulp.start().