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How to retrieve the original graph from a vertex list

Tags:

r

igraph

Problem

Does the igraph package provide an interface to retrieve the original graph from a sub selection of vertices? There is for sure some internal way of doing it, as a simple print shows the total number of vertices in the graph as well as the number of selected vertices and through retro-engineering I was able to get the original graph, but I was wondering whether there is a way supported by the API rather than relying on internal commands.

Code speaks more than words, so here's what I mean:

library(igraph)

G <- make_ring(10)
(v <- V(G)[1:3])
### This output tells me that `v` "knows" about the graph it is taken from
### (namely that it has 10 vertices)
## + 3/10 vertices, from 3fe4e83:
## [1] 1 2 3

The relevant part can be extracted from igraph:::print.igraph.vs

### igraph:::print.igraph.vs
graph <- get_vs_graph(x)

### igraph:::get_vs_graph
at <- attr(seq, "env")
if (class(at) == "weakref") {
   weak_ref_key(at)$me
}

That is, I could do something like:

all.equal(G, igraph:::get_vs_graph(v))
## TRUE

But of course we are using an internal function. So I was wondering whether the API would provide a dedicated way of getting the original graph or whether this is not foreseen?

Why?

Actually, I have a list of vertex sequences coming all from different graphs. Ideally I would like to get a ratio of the number of vertices in my list by the number of vertices in the respective original graph:

set.seed(1)
Gs <- lapply(10 ^ (1:4), make_ring)
Vs <- lapply(Gs, function(G) V(G)[seq(1, sample(gorder(G), 1))])

sapply(Vs, function(v) length(v) / gorder(igraph:::get_vs_graph(v)))
## [1] 0.9000 0.6800 0.6790 0.9725
like image 919
thothal Avatar asked Nov 16 '25 04:11

thothal


1 Answers

Indeed, igraph.vs objects (and igraph.es as well) contain a weak reference that points back to the original graph, and we use igraph:::get_vs_graph() internally to get hold of the original graph.

I can imagine exposing it as a public function in some future version; please file an issue for it in our issue tracker and we can discuss the implications further in the issue tracker.

like image 95
Tamás Avatar answered Nov 17 '25 18:11

Tamás



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