how to insert new variable in (*args,**kwargs) section?

Question

i want to make a decoration method to assign the variable which the function would use but wouldn't be deliver by itself.

for example add new variable y in lambda r,i wrote code in this way but didn't work.

r = lambda x:x+y

def foo(func):
    def wrapped(*args,**kwargs):
        y = 3
        return func(y=y,*args,**kwargs)
    return wrapped

r = foo(r)
print(r(444))

this wouldn't work too

r = lambda x:x+y

def foo(func):
    def wrapped(*args,**kwargs):
        y = 3
        return func(*args,**kwargs)
    return wrapped

r = foo(r)
print(r(444))

Answer 1

kwargs is a casual python dict type, so you can just set the value of the y key to be 3

r = lambda x, y=0:x+y

def foo(func):
    def wrapped(*args,**kwargs):
        print type(kwargs) #  will output <type 'dict'>
        kwargs['y'] = 3
        return func(*args,**kwargs)
    return wrapped

In Understanding kwargs in Python this is explained in details.