I have a project based on django (3.2.10) and sentry-sdk (1.16.0) There is my sentry-init file:
from os import getenv
SENTRY_URL = getenv('SENTRY_URL')
if SENTRY_URL:
    from sentry_sdk import init
    from sentry_sdk.integrations.django import DjangoIntegration
    from sentry_sdk.integrations.redis import RedisIntegration
    from sentry_sdk.integrations.celery import CeleryIntegration
    init(
        dsn=SENTRY_URL,
        integrations=[DjangoIntegration(), RedisIntegration(), CeleryIntegration()],
        traces_sample_rate=1.0,
        send_default_pii=True,
        debug=True,
    )
I have a CustomError inherited from Exception
Every time I raise the CustomError sentry-sdk sends it to the dsn-url.
I want to ignore some class of error or something like this. How can I do this?
You can pass a function that filters the errors to be sent:
from os import getenv
SENTRY_URL = getenv('SENTRY_URL')
if SENTRY_URL:
    from sentry_sdk import init
    from sentry_sdk.integrations.django import DjangoIntegration
    from sentry_sdk.integrations.redis import RedisIntegration
    from sentry_sdk.integrations.celery import CeleryIntegration
  
    def before_send(event, hint):
       if 'exc_info' in hint:
          exc_type, exc_value, tb = hint['exc_info']
          if isinstance(exc_value, CustomError):  # Replace CustomError with your custom error 
             return None
       return event
    init(
        dsn=SENTRY_URL,
        integrations=[DjangoIntegration(), RedisIntegration(), CeleryIntegration()],
        traces_sample_rate=1.0,
        send_default_pii=True,
        debug=True,
        before_send=before_send
    )
You can find more info in the documentation.
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