How to get the name of the calling alias method?

Question

I am having method called link_to_admin then I have aliased another method called simple_link_to

def link_to_admin(name,url,options={})

  # My stuff here
  link_to(name,url,options)          
end

alias_method :simple_link_to, :link_to_admin

Here I am facing one problem if I call link_to_admin, I want print the value into <li> tag

Ex.

def link_to_admin(name,url,options={})

  # My stuff here
   menu = ""
   menu << "<li> #{link_to(name,url,options)}</li>"
   menu.html_safe
end

And if I call simple_link_to no need of <li> tag. So currently I am passing one options like li_required then am checking condition in my method. This is working perfectly, I know this is correct way to do it.

def link_to_admin(name,url,options={})
   menu = ""
   menu << options[:li_required] ? "<li> #{link_to(name,url,options)}</li>" : link_to(name,url,options)
   menu.html_safe
end

But,Before I was trying to find the calling method like simple_method or link_to_admin, so I tried with:

1.__method__
2.caller[0]=~/`(.*?)'/

This is not working as expected.

I am calling simple_method or link_to_admin methods in layout so __method__ is always returning link_to_admin only.

But caller[0]=~/(.*?)'/if am calling fromlayoutmeans, it's returning layout path and if I am calling from any otherhelperorclass` means it's returning current method.

Any other way is there to check method name.

I know this is not good question, could any one please tell me any other way.

Note:- I have created alias_method for naming conversion only. Other than adding <li> tag I am not doing any thing.

Not only here am having this doubt from long back. I know I can define one more method and I can do it.

Leave my scenario, generally I wants to know this answer.

Answer 1

Using __callee__ instead of __method__ will get the name of the alias being run.