How do I strip a string given a list of unwanted characters? Python

Question

Is there a way to pass in a list instead of a char to str.strip() in python? I have been doing it this way:

unwanted = [c for c in '!@#$%^&*(FGHJKmn']
s = 'FFFFoFob*&%ar**^'
for u in unwanted:
  s = s.strip(u)
print s

Desired output, this output is correct but there should be some sort of a more elegant way than how i'm coding it above:

oFob*&%ar

Answer 1

Strip and friends take a string representing a set of characters, so you can skip the loop:

>>> s = 'FFFFoFob*&%ar**^'
>>> s.strip('!@#$%^&*(FGHJKmn')
'oFob*&%ar'

(the downside of this is that things like fn.rstrip(".png") seems to work for many filenames, but doesn't really work)

Answer 2

Since, you are looking to not delete elements from the middle, you can just use.

>>> 'FFFFoFob*&%ar**^'.strip('!@#$%^&*(FGHJKmn')
'oFob*&%ar'

Otherwise, Use str.translate().

>>> 'FFFFoFob*&%ar**^'.translate(None, '!@#$%^&*(FGHJKmn')
'oobar'