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Is there a way with GNU find to find files with a size >= or <= a certain size? I have only found the >, <, == operators, e.g. -size +1M, -size -1M, -size 1M, respectively.
In this blog, the author suggested a combination of multiple -size arguments as in find . -type f -size +1M -size -2M. However, this does not work for my find (GNU findutils) 4.4.2.
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if [ (( $FILESIZE > MAXSIZE)) ]; -> if (( FILESIZE > MAXSIZE )); The arithmetic operators can serve as a conditional expression. (you don't need the $ within ((...)) )
Syntax of find command to find files bigger than given size in Linux. For example, “-size +4G” makes the find command to search for files greater than 4GB. Here, + sign is denote that look for files greater than or equal to N[Type], like in this case, -size +4G will make find command to look for files bigger than 4GB.
Using the -size flag The -size flag is used to find files of a specific size using k for kilobytes, M for megabytes, G for gigabytes, T for terabytes and P for petabytes. However on its own the size specified needs to be an exact match.
Since the operator <= is logically equivalent to not > (Not greater than), these 2 operators can be swapped with each other. In our example, to find files with size less than or equal to 1M, you can look for files not larger than 1M: -not -size +1M.
The same logic can be applied to >= using not <.
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the following command seems to work:
]$ find -version
find (GNU findutils) 4.4.2
find ~ -type f -size '+1k' -a -size '-3k' -exec ls -lah '{}' ';'
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