Get URL from onclick attribute of a tag python

Question

I am trying to access a URL which is present in onclick attribute of a tag using selenium python. It is present in the javascript function. I have tried various techniques to do so but I haven't found the solution yet. I have tried executing the on click function using execute_script method. I have also tried get_attribute to get the onclick function but it returns none. I want to access the url present in openPopUpFullScreen function

Here's the html:

<td class="tdAction">
<div class="formResponseBtn icon-only">
<a href="#fh" onclick="javascript: openPopUpFullScreen('/esop/toolkit/negotiation/rfq/publicRfqSummaryReport.do?rfqId=rfq_229969', '');" class="openNewPage" title="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions">
<img src="/esop_custom/images/buttons/print_button.png" title="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions" alt="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions"><img src="/esop_custom/images/buttons/openNewWindow_button.png" title="(Opens in new window)" alt="(Opens in new window)">
</a>
</div>
</td>

Here's the python code:

url=browser.find_element_by_xpath("//img[@title='Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions']").click()
print(browser.current_url)
#it returns the previous page I am at.

Here's another one:

id=browser.find_element_by_css_selector(".openNewPage").get_attribute("onclick")
print(id)
#it returns none

I need the URL present in openPopUpFullScreen function but I am not able to figure out what would be the right solution to get this done.

Update: I have also tried using beautifulsoup for extraction of the onclick function but it doesn't seem to appear:

Here's my code:

content = browser.page_source.encode('utf-8').strip()
soup = BeautifulSoup(content,"html.parser")
res = soup.find("a",{"class":"openNewPage"})
print(res)
#it returns the complete tag but it does not contain onclick attribute
#i tried using this
res = soup.find("a",{"class":"openNewPage"})[onclick]
#it returns an error NameError: name 'onclick' is not defined

Answer 1

Below

from bs4 import BeautifulSoup


html = '''<td class="tdAction">
<div class="formResponseBtn icon-only">
<a href="#fh" onclick="javascript: openPopUpFullScreen('/esop/toolkit/negotiation/rfq/publicRfqSummaryReport.do?rfqId=rfq_229969', '');" class="openNewPage" title="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions">
<img src="/esop_custom/images/buttons/print_button.png" title="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions" alt="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions"><img src="/esop_custom/images/buttons/openNewWindow_button.png" title="(Opens in new window)" alt="(Opens in new window)">
</a>
</div>
</td>'''


soup = BeautifulSoup(html, features="lxml")
a = soup.find('a')
onclick = a.attrs['onclick']
left = onclick.find("'")
right = onclick.find("'",left+1)
print('URL is: {}'.format(onclick[left+1:right]))

output

URL is: /esop/toolkit/negotiation/rfq/publicRfqSummaryReport.do?rfqId=rfq_229969