I know you can convert the Int to a string and get the digit at position x using the indexer as if it was a char array, but this conversion becomes a bit of an overhead when you're dealing with multiple large numbers.
Is there a way to retrieve a digit at position x without converting the number to a string?
EDIT:
Thank you all, I will benchmark the proposed methods and check if it is any better than converting to a string. Thread will stay unanswered for 24h in case anyone has better ideas.
EDIT 2:
After some simple tests on ulong numbers, I have concluded that converting to strings and extracting the digit can be up to 50% slower compared to the methods provided below, see approved answer.
You could do something like this:
int ith_digit(int n, int i) {
return (int) (n / pow(10, i)) % 10;
}
We can get the ith digit by reducing the number down to a point where that digit we want becomes in the one's place, example:
Let's say you wanted the third digit in 12345, then by reducing it to 123 (by dividing it by 10 i number of times) we can then take the remainder of that number divided by ten to get the last digit, which is the digit we wanted.
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