Get file path without file name

Question

Given a file path

/path/to/some/file.jpg

How would I get

/path/to/some

I'm currently doing

fullpath = '/path/to/some/file.jpg'
filepath = '/'.join(fullpath.split('/')[:-1])

But I think it is open to errors

Answer 1

With os.path.split:

dirname, fname = os.path.split(fullpath)

Per the docs:

Split the pathname path into a pair, (head, tail) where tail is the last pathname component and head is everything leading up to that. The tail part will never contain a slash; if path ends in a slash, tail will be empty. If there is no slash in path, head will be empty.

os.path is always the module suitable for the platform that the code is running on.

Answer 2

Please try this

fullpath = '/path/to/some/file.jpg'

import os
os.path.dirname(fullpath)