Function within a function unknown number of times

Question

How do I use the output of one function as the argument of another. There is an unknown (X) number of functions and each function is different. The argument to the first function is known (lets call it n).

I have tried to create a list of the functions and use the results of one for another, I can't really get anywhere.

list = [function1, function2, function3, function4, function5.....functionX]

def nestedfunction(list, n):
    a_1 = list[0](n)
    a_2 = list[1](a_1)
    a_3 = list[2](a_2)
    a_4 = list[3](a_3)
    a_5 = list[4](a_4)
    ......
    a_x = list [len(list)-1](a_x-1)
    print (a_x)

Thank you for your help.

Answer 1

It's way easier than you made it:

funcs = [function1, function2, function3, function4, function5.....functionX]

def nestedfunction(funcs, n):
    for f in funcs:
        n = f(n)
    return n

Answer 2

Iterate over the list and overwrite n with each iteration, then return it:

def nestedfunction(function_list, n):
    for function in function_list:
        n = function(n)
    return n