Does functional pointers not support instance types in C++

Question

I am trying to understand how to use functional pointers to map the method from instances in C++ like delegates in C#.

class FunctionalPointers
{

public:

    static int IncrementCounter ( int *a, int b )
    {
        return *a += b; 
    }

    int NonStaticIncrementCounter ( int *a, int b )
    {
        return *a += b;
    }
};

//Declare a functional pointer as a separate type.
typedef int ( *AFunctionalPointer ) ( int*, int );

int _tmain(int argc, _TCHAR* argv[])
{
    int a = 10;
    int *ptr = &a;
    *ptr = 200;

    //This works as the methods are static
    AFunctionalPointer funcInstance = FunctionalPointers::IncrementCounter;
    int result = funcInstance( ptr, a );

    //But if I try to make the same call from an
    //instance of a non static method I get an error. Why ?
    FunctionalPointers *functionalPointer = new FunctionalPointers();
    //ERROR : Compiler says it's illegal operation.
    AFunctionalPointer funcClassInstanceType = *functionalPointer->IncrementCounter;

    int instanceResult = funcClassInstanceType( ptr, a );
    return 0;
}

As you can see above, if a static method is assigned to the functional pointer it compiles perfectly but if I try to do the same thing with non static method with the instance of the class, the compiler throws an illegal operation error.

Mapping an instance method to a delegate in C# is very much possible like the snippet below

class Program
{
    static void Main( string[] args )
    {
        int a = 200;
        int b = a;

        FunctionalPointer funcInstance = new FunctionalPointer();
        AFunctionalPointer degegateInstance = funcInstance.Increment;

        int result = degegateInstance( 200, 200 );
    }
}

public delegate int AFunctionalPointer( int a, int b );

class FunctionalPointer
{
    public int Increment ( int a, int b )
    {
        return a += b;
    }

    public int Decrement( int a, int b )
    {
        return a -= b;
    }
}

My question is,

Is it a knowledge gap on my part or is it a part of the rule in C++ to define function pointers in a different way to support instance types.

Answer 1

C++ requires different pointer types for member functions. The C++ FAQ has a whole section on them.

You can get C#-like behavior by using the std::function wrapper from C++11.