Display contents (in hex) of 16 bytes at the specified address

Question

I'm attempting to display the contents of a specific address, given a char* to that address. So far I had attempted doing it using the following implementation

int mem_display(char *arguments) {
    int address = *arguments; 
    int* contents_pointer = (int*)address;
    int contents = *contents_pointer;
    printf("Address %p: contents %16x\n", contents_pointer, contents);              
}

But I keep getting a "Segmentation Fault (Core Dumped)" error. I attempted to make a dummy pointer to test on

char foo = 6;  
char *bar = &foo;

But the error still persists

Answer 1

I'm finding it hard to explain what the problem is because almost every single line in your code is wrong.

Here's what I would do:

void mem_display(const void *address) {
    const unsigned char *p = address;
    for (size_t i = 0; i < 16; i++) {
        printf("%02hhx", p[i]);
    }
    putchar('\n');
}