converting a list of times to total time [closed]

Question

I have 3 lists, one for hours, one for minutes, and one for seconds. What I have done is create a function that will take 3 lists as input and calculate the total amount of time.

My issue is that the function is so redundant and my question to you, is simpy: what is a better way to do this.

Here is my function:

def final_time(hours,minutes,seconds):
    draft_hours = sum(hours)
    draft_minutes = sum(minutes)
    draft_seconds = sum(seconds)
    adding_seconds = str(draft_seconds/60.0)
    second_converting = adding_seconds.split(".")
    seconds_to_minutes = int(second_converting[0])
    seconds_to_seconds = draft_seconds - (seconds_to_minutes * 60)
    total_seconds = str(seconds_to_seconds)
    more_minutes = draft_minutes + seconds_to_minutes
    adding_minutes = str(more_minutes/60.0)
    minute_converting = adding_minutes.split(".")
    minutes_to_hours = int(minute_converting[0])
    minutes_to_minutes = more_minutes - (minutes_to_hours * 60)
    total_minutes = str(minutes_to_minutes)
    total_hours = str(draft_hours + minutes_to_hours)
    return total_hours + " hours, " + total_minutes + " minutes, and " + total_seconds + " seconds."

here is an example:

my_hours = [5, 17, 4, 8]
my_minutes = [40, 51, 5, 24]
my_seconds = [55, 31, 20, 33]
print final_time(my_hours,my_minutes,my_seconds)

above returns:

36 hours, 2 minutes, and 19 seconds.

so it does work, but as you can see, the function is just not a pythonic nor efficient function...what would a better method be?

Answer 1

s = sum(hours)*3600+sum(minutes)*60+sum(seconds)
return '%d hours %d minutes %d seconds'%( s/3600, (s%3600)/60, s%60)

Answer 2

I would probably convert it all to seconds first:

seconds = sum(3600*h + 60*m + s for (h,m,s) in zip(hours,minutes,seconds)

Now break it back down:

n_hours,minutes = divmod(seconds,3600)
n_minutes,n_seconds = divmod(minutes,60)