Confusing calling method in Java

Question

class Parent
{
    private void method1()
    {
        System.out.println("Parent's method1()");
    }
    public void method2()
    {
        System.out.println("Parent's method2()");
        method1();
    }
}

class Child extends Parent
{
    public void method1()
    {
        System.out.println("Child's method1()");        
    }
}
class test {
    public static void main(String args[])
    {
        Parent p = new Child();
        p.method2();
    }
}

I'm confuse why does in Parent::method2() when invoking method1() it will cal Parents method1() and not Childs method1 ? I see that this happens only when method1() is private? Can someone explain me why ?
Thanks you.

Answer 1

This happens based on scoping rules; in Parent the best match for method1 is the class-local private version.

If you were to define method1 as public or protected in Parent and override the method in Child, then calling method2 would invoke Child's method1 instead.

Answer 2

private methods can't be overriden, hence the method1 you specify on Child isn't linked. javac assumes you must mean the method1 on the parent. Changing it to protected will work.