Click Event Handler Issue

Question

I am making a quick application which displays a random number onto a second windows Form. I am making it as a random number generator as when the random number is displayed from the click button event handler. I am having trouble figuring out how to display my random generated number onto my new windows Form. I have created two Forms. Here is my code below:

{
    public partial class Form1 : Form
    {
        Random rnd = new Random();
        int randomnumber;


        public Form1()
        {
            InitializeComponent();
        }

        private void Form1_Load(object sender, EventArgs e)
        {

        }

        private void button1_Click(object sender, EventArgs e)
        {
            randomnumber = rnd.Next(100);
            Form2 r2 = new Form2();
            r2.ShowDialog();

            MessageBox.Show( randomnumber.ToString()); 
// as you see, I displayed it to a MessageBox because
// I was having difficulty showing this value onto the second windows forum named Form 2 
        }
    }
}

// note, this is the code for the first form.

and below is my code for the second form:

{
    public partial class Form2 : Form
    {
        public Form2()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            this.Close();
        }

        private void label5_Click(object sender, EventArgs e)
        {


        }
    }
}

Answer 1

Option 01

You can create a method in Form2 that would assign the value to desired Label control.

public void AssignRandomNumber(int randomNumber)
{
    label5.Text = randomNumber.ToString();
}

And then after generating the Random Number, you can use the method to assign the value.

 randomnumber = rnd.Next(100);
 Form2 r2 = new Form2();
 r2.AssignRandomNumber(randomnumber);
 r2.ShowDialog();

Option 2:

You could do the same with the Constructor of Form2

public Form2(int randomNumber)
{
    InitializeComponent();
    label1.Text = randomNumber.ToString();
}

In this case, your code in Form1 would look like

randomnumber = rnd.Next(100);
Form2 r2 = new Form2(randomnumber);
r2.ShowDialog();